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Open Landing Page later in app

Dhaval Nena

In iOS I need to store all the sent push notifications which user has interacted with in local database and show it in the notifications screen, when user tap on any notification I need to display all the details associated with push like alert body, title, summary, actions etc.

My problem is how can I reopen landing page which was set as action from the UA dashboard. below is my notification payload

 

FOREGROUND NOTIFICATION
{
"^p" = "https://dl.urbanairship.com/binary/public/VX58HvPeSBOnr8fElQAX6g/7585849c-12b7-44e4-b1ec-b1ffd7ab4a8d";
"_" = "24372321-0ff6-4984-a335-cac1bac74332";
aps = {
alert = "Only Push \nAction = DEEP LINK = reward screen\n\n";
};
"com.urbanairship.metadata" = "eyJ2ZXJzaW9uX2lkIjoxLCJ0aW1lIjoxNTUyOTk4OTYwMzM1LCJwdXNoX2lkIjoiYThhMTY5NjctYThkNS00Y2Y4LWFlZDQtMmQ0NWU3NzVmNGJmIn0=";
}

I'm storing value of the field "^p" in database and I need to reopen the same webpage that opened automatically upon interacting with UA push, I can load same link in webview but that is not what I expect, as native webview can't handle deeplink and all that associated with button in landing page, request to guide me in achieving my requirement.

Thanks,

Dhaval

 

 

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Hi Dhavel,

You should be able to achieve this through the custom actions.

Kind regards,
Chilun Liu
Senior Technical Support Engineer
Urban Airship

25 Lavington Street | London | SE1 0NZ
Portland | San Francisco | London | New York | Gurgaon

 

chilun liu 0 votes
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Hi Chilun,

Thanks for the quick reply.

I tried below code for opening landing page, however still unable to open the Landing Page

 

// REGISTERING LANDING PAGE ACTION

 

let customAction = UAAction(block: { (args, actionHandler) in
print("Action performing with args : \(args)")
actionHandler(UAActionResult.init(value: "test.."))
})
UAirship.shared()?.actionRegistry.register(customAction, name: "landing_page_action")

 

// RUNNING ACTION

let url = "https://dl.urbanairship.com/binary/public/VX58HvPeSBOnr8fElQAX6g/65753117-fd14-4112-85a2-043f9e7c57d4"
UAActionRunner.runAction(withName: name, value: [UALandingPageURLKey:url], situation: UASituation.manualInvocation, metadata: nil) { (actionResult) in
print("ACTION FINISHED \(actionResult.status)")
}

 

Can you please help with code snippet to open landing page, appreciate your help.

Thanks much,

Dhaval

Dhaval Nena 0 votes
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